打开附件如下
勒索病毒我去上网查了一下，发现是通过加密数据，所以这个题可能和加密有关，除了勒索病毒还有一个enflag.txt打开如下
先不管这个
第一步查壳这个exe程序
无壳。
第二步用ida32位打开这个
shift+f12查看字符
有个充值成功，跟进
可以看到这个字符串 DHmqqvqxB^||zll@Jqjkwpmvez{
可以知道是异或，脚本如下
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| s="DH~mqqvqxB^||zll@Jq~jkwpmvez{"
key=""
for c in s:
key+=chr(ord(c)^0x1f)
print(key)
|
[Warnning]Access_Unauthorized结合这个可以猜测这是个密钥，那个enflag是个密文，用winhex打开
0xC3,0x82,0xA3,0x25,0xF6,0x4C,
0x36,0x3B,0x59,0xCC,0xC4,0xE9,0xF1,0xB5,0x32,0x18,0xB1,
0x96,0xAe,0xBF,0x08,0x35
把这个放进data
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| #include<stdio.h>
void rc4_init(unsigned char* s, unsigned char* key, unsigned long Len_k)
{
int i = 0, j = 0;
char k[256] = { 0 };
unsigned char tmp = 0;
for (i = 0; i < 256; i++) {
s[i] = i;
k[i] = key[i % Len_k];
}
for (i = 0; i < 256; i++) {
j = (j + s[i] + k[i]) % 256;
tmp = s[i];
s[i] = s[j];
s[j] = tmp;
}
}
void rc4_crypt(unsigned char* Data, unsigned long Len_D, unsigned char* key, unsigned long Len_k)
{
unsigned char s[256];
rc4_init(s, key, Len_k);
int i = 0, j = 0, t = 0;
unsigned long k = 0;
unsigned char tmp;
for (k = 0; k < Len_D; k++) {
i = (i + 1) % 256;
j = (j + s[i]) % 256;
tmp = s[i];
s[i] = s[j];
s[j] = tmp;
t = (s[i] + s[j]) % 256;
Data[k] = Data[k] ^ s[t];
}
}
int main()
{
unsigned char key[] = "[Warnning]Access_Unauthorized";
unsigned long key_len = sizeof(key) - 1;
unsigned char data[] = { 0xC3,0x82,0xA3,0x25,0xF6,0x4C,
0x36,0x3B,0x59,0xCC,0xC4,0xE9,0xF1,0xB5,0x32,0x18,0xB1,
0x96,0xAe,0xBF,0x08,0x35};
rc4_crypt(data, sizeof(data), key, key_len);
for (int i = 0; i < sizeof(data); i++)
{
printf("%c", data[i]);
}
printf("\n");
}
|
运行如下
flag{RC4&->ENc0d3F1le}
